SOLUTION: Please help me solve this equation:
You commute 56 miles one way to work. The trip to work takes 10 minutes longer than the trip to home. Your average speed on the trip home is
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Question 173044: Please help me solve this equation:
You commute 56 miles one way to work. The trip to work takes 10 minutes longer than the trip to home. Your average speed on the trip home is 8 miles per hour faster. What is your average speed on the trip home?
thank you!!!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: 10 minutes = 1/6 of an hour
Since the distance of the commute is 56 miles, this means that
Going to Work:
Since "The trip to work takes 10 minutes longer than the trip to home", this means that the time is (in minutes) or (in hours)
We'll use the expression
Start with the distance rate time formula
Plug in and replace "t" with
Combine and to get
Divide both sides by to isolate "r"
Multiply 56 by the reciprocal of .
Multiply 56 and 6 to get 336
So after isolating "r", we get
----------------------------------
Coming Home:
Now because the "average speed on the trip home is 8 miles per hour faster", this means that the new rate is
Go back to the distance rate time formula
Plug in (the commute distance hasn't changed) and replace "r" with (since the speed is 8 mph greater)
Plug in
Distribute
Multiply EVERY term by the LCD to clear the fractions.
Distribute
Subtract 336t from both sides. Subtract 56 from both sides.
Combine like terms.
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for t
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the possible time values (coming home) are or
However a negative time does NOT make sense. So the only answer is
So the time to commute home is 1 hour.
Note: This means that the time to get to work is 1 hour and 10 minutes (or 70 minutes)
Go back to the distance rate time formula
Plug in and (which is the time coming home)
Multiply
=====================================================
Answer:
So the solution is
This means that the average speed coming home is 56 miles per hour.
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