You can
put this solution on YOUR website!THE ELECTRIC CURRENT I, IN AMPERES, IN A CIRCUIT VARIES DIRECTLY AS THE VOLTAGE V. WHEN 12 VOLTS ARE APPLIED, THE CURRENT IS 4 AMPERES. WHAT IS THE CURRENT WHEN 18 VOLTS ARE APPLIED?
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I = kV
Find "k":
4 = k*12
k = 4/12 = 1/3
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Equation: I = (1/3)V
If 18 volts are applied you get:
I = (1/3)*18
I = 6 amps.
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Cheers,
Stan H.