# SOLUTION: 5.1.6. what are all of the trigonomic values given that cot=-3 and sin= square root 10/10

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 Click here to see ALL problems on Miscellaneous Word Problems Question 169985: 5.1.6. what are all of the trigonomic values given that cot=-3 and sin= square root 10/10Answer by stanbon(57246)   (Show Source): You can put this solution on YOUR website!what are all of the trigonomic values given that cot=-3 and sin= square root 10/10 --------------------- Keep in mind that x^2 + y^2 = r^2 ------------ cot=-3 = -3/1 Since cot = x/y, x = -3 and y = 1 Therefore r = sqrt(-3)^2 + 1^2) = sqrt(10) --------------------- Then: sin = y/r = 1/sqrt(10) = sqrt(10)/10 cos = x/r = -3/sqrt(10) tan = y/x = -1/3 csc = r/y = sqrt(10) sec = r/x = -sqrt(10)/3 cot = -3 ========================= Cheers, Stan H.