SOLUTION: A company is trying to determine which computer system to install. System A: consists of a central minicomputer costing $100,000 plus desktop terminals costing $800 each. System
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Question 169306: A company is trying to determine which computer system to install. System A: consists of a central minicomputer costing $100,000 plus desktop terminals costing $800 each. System B: is a network of desktop personal computers that costs $16,000 to install plus $1,200 for each desktop personal computer. How many desktop setups would the company need in order to make the costs of the two systems equal?
trying to solve I ask: how many people are getting a computer? Number of people = x
how do I write out each problem ? 100,000 + 800(x) I am stumped, then 16,000 + 1,200 (x) ?
Your help would be greatly appreciated. I am unable to find a sample in my book .
Thank You
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
your on the right track:
:
let A = the number of desktops
:
these two must equal each other in terms of costs so set the two equation = to one another.
:
100000+800A=16000+1200A
:
400A=84000
:
which is the number of desktops it would take to make these two systems equal
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