SOLUTION: Golden Painting. An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? L/W = W/L-W
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Question 166432: Golden Painting. An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? L/W = W/L-W
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
in a golden rectangle, if the length of the painting is 36 inches, then the width of the painting would be either (1+5^(1/2))/2 times that, or that divided by [(1+5^(1/2))/2]
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[(1+5^(1/2))/2] is equal to the sum of (1 + square root of 5) divided by 2.
[(1+5^(1/2))/2] is equal to 1.618033989
that number is called PHI. PHI is a greek letter. i believe it's pronounced FIE or FYE.
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if the length is the longest dimension, then the width = 36 / PHI = 22.2492236 inches.
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if the length is the shortest dimension, then the width = 36 * PHI = 58.2492236
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