SOLUTION: A cyclist traveled at a rate of 32 mph to visit a nearby town. They cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby

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Question 166429: A cyclist traveled at a rate of 32 mph to visit a nearby town. They cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby town.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
distance going call d1
distance returning call d2
d1=d2
time returning call t
time going call t-6.3
rate going is 32mph
rate returning is 10mph
d1=32(6.3-t)
d2=10t
32(6.3-t)=10t
201.6-32t=10t
42t=201.6
t=4.8
so d=10%284.8%29=48miles