SOLUTION: A cyclist traveled at a rate of 32 mph to visit a nearby town. They cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby
Algebra.Com
Question 166429: A cyclist traveled at a rate of 32 mph to visit a nearby town. They cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby town.
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
distance going call d1
distance returning call d2
d1=d2
time returning call t
time going call t-6.3
rate going is 32mph
rate returning is 10mph
d1=32(6.3-t)
d2=10t
32(6.3-t)=10t
201.6-32t=10t
42t=201.6
t=4.8
so
RELATED QUESTIONS
a cyclist traveled at at rate of 32 mph to visit a nearby town. The cyclist averaged 10... (answered by checkley77)
A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist averaged 10... (answered by checkley77)
A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist averaged 10... (answered by ankor@dixie-net.com)
. A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist averaged 10... (answered by edjones)
A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist averaged 10... (answered by ptaylor)
A cyclist traveled at a rate of 24 mph to visit a nearby town. The cyclist averaged 18... (answered by rebalchick13)
A cyclist traveled at a rate of 24 mph to visit a nearby town. The
cyclist averaged 18... (answered by checkley71)
A cyclist traveled at a rate of 24 mph to visit a nearby town. the cyclist averaged 18... (answered by checkley75)
A cyclist traveled at a rate of 24 mph to visit a nearby town. The cyclist averaged 18... (answered by ankor@dixie-net.com)