SOLUTION: THE TIME REQUIRED TO EMPTY A TANK VARIES INVERSELY AS THE RATE OF PUMPING. IF A PUMP CAN EMPTY A TANK IN 45 MINUTES AT THE RATE OF 600 GALLONS PER MINUTE, HOW LONG WILL IT TAKE THE

Question 166112: THE TIME REQUIRED TO EMPTY A TANK VARIES INVERSELY AS THE RATE OF PUMPING. IF A PUMP CAN EMPTY A TANK IN 45 MINUTES AT THE RATE OF 600 GALLONS PER MINUTE, HOW LONG WILL IT TAKE THE PUMP TO EMPTY THE SAME TANK AT THE RATE OF 1000 GALLONS PER MINUTE?
Answer by midwood_trail(310) (Show Source): You can put this solution on YOUR website!
THE TIME REQUIRED TO EMPTY A TANK VARIES INVERSELY AS THE RATE OF PUMPING. IF A PUMP CAN EMPTY A TANK IN 45 MINUTES AT THE RATE OF 600 GALLONS PER MINUTE, HOW LONG WILL IT TAKE THE PUMP TO EMPTY THE SAME TANK AT THE RATE OF 1000 GALLONS PER MINUTE?
Let t = equal the time required to empty a tank
Let r = rate of pumping
Let k = the constant of variation
t varies inversely as r, is written:
t = k/r
600 = k/45
600 (45) = k
27,000 = k
Find t when r = 1000
t = 27,000/1000
t = 27 minutes

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