SOLUTION: I put in this problem before and I forgot to put something in the problem. I was wondering if someone could answer this problem again. I would deeply appreciate it. Please and Than

Question 154040This question is from textbook Algebra and Trigonometry Structure and Method book 2
: I put in this problem before and I forgot to put something in the problem. I was wondering if someone could answer this problem again. I would deeply appreciate it. Please and Thank you. I have tried to work this problem and I can't seem to get it.
In a walkathon to raise money for charity, Elisa walked a certain distance at 5 mi/h and then jogged twice that distance at 8 mi/h. Her total time walking and jogging was 2 h and 15 min. How many miles long was the walkathon? (hint: time=distance over rate.) This question is from textbook Algebra and Trigonometry Structure and Method book 2

Found 2 solutions by orca, scott8148:
Answer by orca(409) (Show Source): You can put this solution on YOUR website!
Let x be the distance she walked,
then the distance she jogged is 2x.
The time walking was
The time jogging was
The total time is
As the total time is 2 hours and 15 minutes, we have

Solving for x, we have

(multiply both sides by 20)

So
the distance she walked is 5 miles
the distance she jogged is 10 miles.

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
a decent hint __ let's use it

" Elisa walked a certain distance at 5 mi/h" __ Tw=d/5

"then jogged twice that distance at 8 mi/h" __ Tj=2d/8=d/4

total distance equals d+2d or 3d __ total time equals 2h and 15 min or 9/4 h

Tw+Tj=9/4 __ substituting __ (d/5)+(d/4)=9/4 __ multiplying by 20 __ 4d+5d=45 __ 9d=45 __ dividing by 9 __ d=5

total distance equals 3*(5) or 15 mi
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