SOLUTION: I am having trouble with this problem and I was wondering if anyone could help me? I would deeply appreciate it. Please and Thank you!!! If one side of a square is increased

Question 154022This question is from textbook Algebra and Trigonometry Structure and Method
: I am having trouble with this problem and I was wondering if anyone could help me? I would deeply appreciate it. Please and Thank you!!!

If one side of a square is increased by 8cm and an adjacent side decreased by 2cm, a rectangle is formed whose perimeter is 40cm. Find the length of a side of the square. This question is from textbook Algebra and Trigonometry Structure and Method

Answer by orca(409) (Show Source): You can put this solution on YOUR website!
Let x be the length of the sides of the square.
The dimensions of the newly formed rectangle are as follows:
Width: x-2
Length: x+8
So the perimeter is 2(x-2)+2(x+8).
As the perimeter is given as 40, we have
2(x-2)+2(x+8)=40
Solving for x, we obtain:
2x - 4 + 2x + 16 = 40
4x + 12 = 40
4x = 28
x = 7
So the length of the side of the square is 7 cm.

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