SOLUTION: Please help me. I have been working on this problem with a classmate of mine and we cant figure this one out at all. We were thinking.... x + y = 6 and 8x + 3y = 60 However, th

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Question 153852: Please help me. I have been working on this problem with a classmate of mine and we cant figure this one out at all.
We were thinking.... x + y = 6 and 8x + 3y = 60 However, thats not correct.
Lisa Chung wants to cover a 6 miles course in 1 hour by running part of the way and walking the rest. She also wants to make a 5 minute stop for water. Lisa runs 8 mph and walks 3 mph. How many miles will she have to run?
Please help and as always - I do appreciate you.

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Lisa Chung wants to cover a 6 miles course in 1 hour by running part of the way and walking the rest. She also wants to make a 5 minute stop for water. Lisa runs 8 mph and walks 3 mph. How many miles will she have to run?
------------------------
Let "x" be the miles Lisa runs; Then she will walk "6-x" miles.
------------
Her running time: distance/rate = x/8 hrs
Her walking time: distance/rate = (6-x)/3 hrs
-------------------------------
EQUATION
run time + walk time + (5/60)water time = 1 hr
x/8 + (6-x)/3 + (5/60) = 1
Multiply thru 120:
15x + 40(6-x) + 10 = 120
15x + 240 - 40x + 10 = 120
25x = 130
x = 5.2 miles (distance she must run)
6-x = 0.8 miles (distance she must walk)
=======================
Cheers,
Stan H.

Answer by Edwin McCravy(20059)   (Show Source): You can put this solution on YOUR website!
Edwin's solution:
Please help me. I have been working on this problem with a classmate of mine and we cant figure this one out at all.
We were thinking.... x + y = 6 and 8x + 3y = 60 However, thats not correct.
Lisa Chung wants to cover a 6 miles course in 1 hour by running part of the way and walking the rest. She also wants to make a 5 minute stop for water. Lisa runs 8 mph and walks 3 mph. How many miles will she have to run?
Please help and as always - I do appreciate you.

Your second equation is wrong.

Let x = the distance she runs
Ley y = the distance she walks

x + y = 6

That's the distance equation.

Now we must make a time equation.

We must use , not "distance times rate".

The time she runs = 

The time she walks = 

Now since she stops to rest 5 minutes, the total time
she walks and runs is only 55 minutes.  But we must change
55 minute to hours by dividing it by 60.  So the total
time is ths of an hour, which reduces to ths
of an hour.  So the second equation is



Then we clear that of fractions by multiplying
through by the LCD 




                   




So the system to solve is



Multiply the first equation through by -3
to eliminate the x's.  Add vertically term 
by term:

-3x - 3y = -18
 3x + 8y =  22
--------------
      5y = 4
       y = ths of a mile she runs.



Now multiply the first equation through by -8
to eliminate the y's.  Add vertically term by term:

-8x - 8y = -48
 3x + 8y =  22
--------------
-5x      = -26
  x      = 
       x =  = miles she walks. 

Edwin

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