# SOLUTION: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y - 72 cubic centimet

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 Click here to see ALL problems on Miscellaneous Word Problems Question 151150: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?Answer by ankor@dixie-net.com(15622)   (Show Source): You can put this solution on YOUR website!Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters. : If the new volume is y^3 - 13y^2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height? : Use synthetic division, divide the vol by the width : .....__________________ 6 | 1 - 13 + 54 - 72 ............+6 - 42 + 72 .....------------------ .......1 - 7 + 12 + 0 : The quotient: y^2 - 7y + 12 ; Which factors to (y-4)(y-3) ; The new length = +4, new height = +3 : : You can check solution: (y-6)*(y-4)*(y-3)