SOLUTION: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y

SOLUTION: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y - 72 cubic centimet

Question 151150: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters.
:
If the new volume is y^3 - 13y^2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
:
Use synthetic division, divide the vol by the width
:
.....__________________
6 | 1 - 13 + 54 - 72
............+6 - 42 + 72
.....------------------
.......1 - 7 + 12 + 0
:
The quotient: y^2 - 7y + 12
;
Which factors to (y-4)(y-3)
;
The new length = +4, new height = +3
:
:
You can check solution: (y-6)*(y-4)*(y-3)

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