SOLUTION: hi, i was wondering if you could help me this problem #24 pg. 11 in the College Geometry 2nd Edition, Musser, Trimpe, and Maurer the problem is 24. Greg has 1002 meters of f

Question 145537This question is from textbook College Geometry Musser, Trimpe, and Maurer
: hi, i was wondering if you could help me this problem #24 pg. 11 in the College Geometry 2nd Edition, Musser, Trimpe, and Maurer
the problem is
24. Greg has 1002 meters of fencing. He will use all the fencing to enclose a rectangular region that is four times as long as it is wide. One of the longer sides is bordered by a river, so that side will not be fenced. What will be the dimensions of the region?
Please help me, and also include work. Thank you very much
This question is from textbook College Geometry Musser, Trimpe, and Maurer

Answer by 24HoursTutor.com(40) (Show Source): You can put this solution on YOUR website!
Let the length of the wide side be = b
So, the long side will be = l = 4b
For fencing we generally calculate the perimeter of the area to be fenced which is given by the formula : 2 (l + b) where l stands for length and b for breadth. This basically means we have 2 lengths to cover and 2 breadths to cover with our fence. But, in this problem one length is covered by a river so our formula is reduced to :
l + 2b
which we know is 1002. So our equation would be
4b + 2b = 1002
6b = 1002
b = 1002/6
b = 167
l = 4b = 4 X 167 = 668
Ans. : The length of the region is 668m while the breadth is 167m.
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