SOLUTION: A personn invested 10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income form the smalle
Algebra.Com
Question 145109: A personn invested 10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income form the smaller part. what is the smaller part of the the investment?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.06X=.05(10,000-X)+160
.06X=500-.05X+160
.06X+.05X=660
.11X=660
X=660/.11
X=$6,000 INVESTED @ 6%.
10,000-6,000=4,000 INVESTED @ 5%.
PROOF
.06*6,000=.05*4,000+160
360=200+160
360=360
RELATED QUESTIONS
A person invested $10,000.00. The greater part is invested at 6% and the remainder at 5%. (answered by checkley71)
please help me .A person invested $10,000. the greater part is invested at 6% and the... (answered by gonzo)
A person invested $10,000. The greater part is invested at 6% and the remainder at 5%.... (answered by checkley77)
A person invested $10,000. The greater part is invested at 6% and the remainder at 5%.... (answered by JBarnum)
A person invested $10,000. The greater part is invested at 6% and the remainder at 5%.... (answered by mananth)
A person invested $10,000. The greater part is invested at 6% and the remainder at 5%.... (answered by jorel1380)
A person invested $10,000. The greater part is invested at 6% and the remainder at 5%.... (answered by scott8148)
a person invested $10,000 .the greater part is invested at 6% and the remainer at 5% .... (answered by stanbon)
A part of P10,000 is invested at 4% and the remainder at 3. ½%. The annual
income from (answered by Theo)