SOLUTION: Solve: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curv

Question 145009: Solve:
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50mph? round to the nearest pound of force.
Please help...I do not know where to begin with this one!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve.
F = k[ws^2/r]
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If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet
3600 = k[1800*20^2/600]
k = 3
Equation:
F = 3[ws^2/r]
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What force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round to the nearest pound of force?
F = 3[1800*50^2/570]
F = 23684
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Cheers,
Stan H.

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