SOLUTION: A plane is flying the 3,458 mile trip from New York City to London has a 50 MPH tailwind. The flight's Point of No Return is the point at which the flight time required to return t

Question 141347: A plane is flying the 3,458 mile trip from New York City to London has a 50 MPH tailwind. The flight's Point of No Return is the point at which the flight time required to return to New York is the same a the time required to continue to London. If the speed on the plane in still air is 360 MPH, how far is New York from the point of no return?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A plane is flying the 3,458 mile trip from New York City to London has a 50 MPH tailwind. The flight's Point of No Return is the point at which the flight time required to return to New York is the same a the time required to continue to London. If the speed on the plane in still air is 360 MPH, how far is New York from the point of no return?
:
From the given information we can say:
360 + 50 = 410 mph speed (relative to the earth) with the wind
360 - 50 - 310 mph speed against the wind
:
Let d = dist to New York from point of no return
Then
(3458-d) = dist to London from point of no return
:
Write a time equation: Time = dist/speed
:
Return to N.Y time = Continue to London time
=
Cross multiply:
410d = 310(3458-d)
:
410d = 1071980 - 310d
:
410d + 310d = 1071980
:
720d = 1071980
d =
d = 1488.86 mi from N.Y.
:
:
Check solution by finding the distance to London and calculating the time to both:
3458 - 1488.86 = 1969.14 mi to London
:
Time to N.Y.: 1488.86/310 = 4.8 hrs
Time to Lond: 1969.14/410 = 4.8 hrs
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