SOLUTION: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a fo
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Question 136945This question is from textbook Intermediate Algebra
: The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force?
This question is from textbook Intermediate Algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve.
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F = k*w*s^2/r
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If a force of 3600 pounds is needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet
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3600 = k*1800*20^2/600
k = 3
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Equation for your problem:
F = 3*w*s^2/r
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what force would be required to keep the same car from skidding on a curve of radius 570 feet at 50 mph? Round your answer to the nearest pound of force?
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F = 3*1800*50^2/570
F = 23684.21 lbs. of force
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Cheers,
Stan H.
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