# SOLUTION: the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times its width find the perimiter of the rectangle

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times its width find the perimiter of the rectangle      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Miscellaneous Word Problems Question 135595: the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times its width find the perimiter of the rectangleAnswer by dbashant(7)   (Show Source): You can put this solution on YOUR website!length l times width w = area A Also we know that the length is 1cm more than 3 times the width. Plugging that back into the Area equation, we get: Simplify Two Real solutions!! Either or Either or Either or Because having a negative answer for a length doesn't make sense, we can disregard the -13/3 answer for w. So, width is 4. Length is 3 times width plus one, or 13. Perimeter is - will leave that to the student to answer.