SOLUTION: the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times its width find the perimiter of the rectangle

Question 135595: the area of a rectangle has an area of 52cm^2 and its length is 1 cm more than 3 times its width find the perimiter of the rectangle
Answer by dbashant(7) (Show Source): You can put this solution on YOUR website!
length l times width w = area A

Also we know that the length is 1cm more than 3 times the width.

Plugging that back into the Area equation, we get:

Simplify

Two Real solutions!!
Either or
Either or
Either or
Because having a negative answer for a length doesn't make sense, we can disregard the -13/3 answer for w. So, width is 4. Length is 3 times width plus one, or 13.
Perimeter is - will leave that to the student to answer.
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