SOLUTION: The area of a rectangular field is 1200m^2. Two parallel sides are fenced with aluminum at $20/m. The remaining two sides are fenced with steel at $10/m. The total cost of the fenc

Question 135389: The area of a rectangular field is 1200m^2. Two parallel sides are fenced with aluminum at $20/m. The remaining two sides are fenced with steel at $10/m. The total cost of the fencing is $2200. What is the length of each side fenced with aluminum and what is the length of each side fenced with steel?
Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
XY=1200 OR X=1200/Y
2*20X+2*10Y=2200
40X+20Y=2200
40(1200/Y)+20Y=2200
48,000/Y+20Y=2200
(48,000+20Y^2)/Y=2200 CROSS MULTIPLY
48,000+20Y^2=2200Y
20Y^2-2200Y+48,000=0
20(Y^2-110Y+2,400)=0
20(Y-30)(Y-80)=0
Y-30=0
Y=30 ANSWER
X=1200/30
X=40 ANSWER
Y-80=0
Y=80 ANSWER
X=1200/80
X=15 ANSWER.
PROOFS:
30*40=1200
1200=1200
80*15=1200
1200=1200
2*20*40+2*10*30=2200
1600+600=2200
2200=2200
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Big mistake Sorry, it's good someone else did it right!!
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