SOLUTION: Alright, the problem is "A mixture of chlorine and water containsa total of 66 gallons of liquid. There are 55 gallons of pure chlorine in the mixure. What percent of the mixture

Question 13431: Alright, the problem is "A mixture of chlorine and water containsa total of 66 gallons of liquid. There are 55 gallons of pure chlorine in the mixure. What percent of the mixture is water? What percent of the mixture is chlorine? Round to the nearlest percent, if necissary."
I got this far...
(11 * ___) + (55 * 1) = 66 * ___
can't find the blanks.
help much appreciated, and thanks in advance
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
From your set up, I think you are thinking of a different type of mixture problem. In this problem you are given that there are 66 gallons of mixture, of which 55 gallons are pure chlorine, and the other 11 gallons are water.

This means that
of the mixture is water = 16 2/3 %
of the mixture is chlorine = 83 1/3%

This rounds to 17% water, 83% chlorine.

R^2 at SCC
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