SOLUTION: Thirty-eight teams are in a tournament. If each team plays every other team only once, then how many games will occur?
Algebra.Com
Question 132838:  Thirty-eight teams are in a tournament. If each team plays every other team only once, then how many games will occur? 
Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
 each of 38 teams plays 37 other teams __ BUT - A playing B is the same as B playing A
so, 38*37/2 
RELATED QUESTIONS
6 teams are involved in a round robin tournament. In a tournament, each team plays every... (answered by ewatrrr)
In a round tournament every team plays every other team once.
Example: For a three teams  (answered by stanbon)
In a baseball tournament consisting of twelve teams, in which each team plays every other  (answered by solver91311,greenestamps)
In a ping pong tournament consisting of twelve teams, each team plays every other team... (answered by ikleyn)
7 teams are in the Christmas Basketball Tournament. Each team will play each other   only  (answered by lynnlo)
In a round-robin tournament, each team must play every other team once. How many games... (answered by richard1234)
Hi. Can you help me solve this? I'm stuck.
How many teams are in a league that... (answered by rapaljer)
In a basketball tournament, there are four teams, and each team plays against every other  (answered by CPhill,ikleyn)
In a round robin tournament, each team plays every other team once. The formula... (answered by math_helper)