SOLUTION: The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising , find its length and its width.
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Question 128350: The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising , find its length and its width.
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
Let "x" ft be the width of the rectangle
So lenght will be "3 + x" ft
Given area = 40 ft^2
We know that the area of the rectangle is given by lenght times breadth
40 = x * (x + 3)
40 = x^2 + 3x
==> x^2 + 3x - 40 = 0
==> by the method of factoring we find
==> x^2 + 8x - 5x - 40 = 0
==> x(x + 8) - 5(x + 8) = 0
==> x = 5 Or x = -8
We dont consider the negative values of x.
Therfore x = 5 ft will be the width
and x + 3 = 5 + 3 = 8ft will be the lenght of the rectangle
thus the solution
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