# SOLUTION: 1) Working alone, Coleen can paint a house in 2hr less than James. Working together, they can paint the house in 10hr. How long would it take James to paint the house?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: 1) Working alone, Coleen can paint a house in 2hr less than James. Working together, they can paint the house in 10hr. How long would it take James to paint the house?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Miscellaneous Word Problems Question 127987: 1) Working alone, Coleen can paint a house in 2hr less than James. Working together, they can paint the house in 10hr. How long would it take James to paint the house?Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!J(J-2)/[J+(J-2)]=10 (J^2-2J)/(2J-2)=10 NOW CROSS MULTIPLY J^2-2J=10(2J-2) J^2-2J=20J-20 J^2-2J-20J+20=0 J^2-22J+20 USING THE QUADRATIC EQUATION: WE GET: J=(22+-SQRT[-22^2-4*1*20])/2*1 J=(22+-SQRT[484-80])/2 J=(22+-SQRT404)/2 J=(22+-20.1)/2 J=(22+20.1)/2 J=42.01/2 J=21.05 HOURS - TIME FOR JAMES TO PAINT THE HOUSE ALONE. PROOF: 21.05*19.05/(21.05+19.05)=10 401/40.1=10 10=10