SOLUTION: ONE NUMBER IS 12 MORE THAN ANOTHER. THE SUM OF THE SMALLER NUMBER AND TWICE THE LARGER NUMBER IS 39. FIND THE LARGER NYMBER.

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Question 126711: ONE NUMBER IS 12 MORE THAN ANOTHER. THE SUM OF THE SMALLER NUMBER AND TWICE THE LARGER NUMBER IS 39. FIND THE LARGER NYMBER.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the smaller number a
and the larger number b
b+=+a+%2B+12
a+%2B+2b+=+39
rearrange the 1st equation
a+-+b+=+-12
multiply both sides by -1
-a+%2B+b+=+12
a+%2B+2b+=+39
Add these equations
3b+=+51
b+=+17
a+=+39+-+2b
a+=+39+-+34
a+=+5
The larger number is 17
check answer
b+=+a+%2B+12
a+%2B+2b+=+39
---------------
17+%2B+5+=+12
5+%2B+34+=+39
OK