SOLUTION: The sum of both digits, of either of two two-digit numbers, in whatever order the digits are written, is 9. The square of either of the digits of either number, minus the product

Question 126540: The sum of both digits, of either of two two-digit numbers, in whatever order the digits are written, is 9. The square of either of the digits of either number, minus the product of both digits, plus the square of the other digit is the number 21. The numbers are _______?
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x="one digit" and y="other digit"

x+y=9 __ x=9-y

x^2-xy+y^2=21 __ substituting __ (9-y)^2-(9-y)y+y^2=21 __ 81-18y+y^2-9y+y^2+y^2=21

dividing by 3 __ y^2-9y+20=0 __ (y-5)(y-4)=0
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