SOLUTION: I don't really know where to place this problem, because it comes in the guide of a contest exam, so I don't know what theme are they talking about, but the problem is like this:

Question 126344: I don't really know where to place this problem, because it comes in the guide of a contest exam, so I don't know what theme are they talking about, but the problem is like this:
If (x+y)^2=17 and xy=3, then x^2+y^2=
a.20
b.17
c.14
d.11
Can you tell me which theme are they talking about and how to solve it... Thank you...
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the first equation

Foil the left side

Notice how the second equation is and the 2nd step has an "2xy" term in it. So let's multiply both sides of by 2

So this means we can replace the "2xy" term in with 6

Replace with 6

Subtract 6 from both sides

Combine like terms

Answer:

So our answer is which means that the answer is D)
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