SOLUTION: How many litrs of 20% alcohol solution must be mixed with a 60% solution to obtain 40 litres of a 35% solution?
Algebra.Com
Question 124524: How many litrs of 20% alcohol solution must be mixed with a 60% solution to obtain 40 litres of a 35% solution?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.2x+.6(40-x)=.35*40
.2x+24-.6x=14
-.4x=14-24
-.4x=-10
x=-10/-.4
x=25 liters of 20% are needed.
proof.
.2*25+.6(40-25)=14
5+.6*15=14
5+9=14
14=14
RELATED QUESTIONS
How many litres of a 10% alcohol solution should be mixed with 12 litres of a 20% alcohol (answered by josgarithmetic)
How many Liters of a 50% alcohol solution must be mixed with 40 Liters to obtain a 60... (answered by ptaylor)
how many gallons of 60% alcohol solution must be mixed with 60 gallons of 14% solution to (answered by josgarithmetic)
how many liters of 25% alcohol must be mixed with 40 liters of a 35% alcohol solution to... (answered by Fombitz)
How many liters of a 10% alcohol solution must be mixed with 20 litres of a 90% solution... (answered by rwm)
How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40... (answered by stanbon)
How many gallons of a 70% alcohol solution must be mixed with 50 gallons of a 20%... (answered by stanbon)
How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14%... (answered by josgarithmetic)
"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 (answered by stanbon)