SOLUTION: A TEST IS WORTH 150 PTS. THERE ARE 46 3 AND 5 PT QUESTIONS. HOW MANY OF EACH IS ON THE TEST?

Question 124214: A TEST IS WORTH 150 PTS. THERE ARE 46 3 AND 5 PT QUESTIONS. HOW MANY OF EACH IS ON THE TEST?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let t be the number of 3 pt queations.
Let f be the number of 5 pt queations.
.
t+f=46
3t+5f=150
.
40 three point questions and 6 five pointers.
Ed
.

Solved by pluggable solver: Linear Systems by Addition

We'll solve the system:

by elimination by addition.To eliminate by addition, we need to set both coefficients of x to numbers with changed signs, i.e a and -a. Since in the second equation we have 3 as our coefficient for x, to get -1 we have to multiply all terms of the second equation by which is equal to -0.333333333333333.

Multiplying, we get on our second equation:

Adding both equations we get:

Since 1 and -1 cancel out, we have a linear equation:Therefore, we know that f = 6.

Plugging that in into the first equation gives us:

Therefore, our answer is:

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