SOLUTION: Please help me solve this problem. "Three seconds after release, the height of an object is {{{ (1/2)(-32)(3^2) }}} feet below the point of release. What is this height?
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Question 122815: Please help me solve this problem. "Three seconds after release, the height of an object is feet below the point of release. What is this height? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Please help me solve this problem. "Three seconds after release, the height of an object is (1/2)(-32)(3^2) feet below the point of release. What is this height?
:
This is the equation for falling objects usually written"
h = -16t^2
Where t = time in seconds and h is falling distance in feet
:
In your problem
h = -16(3^2)
h = -16 * 9 = -144 ft after 3 seconds, negative because it is falling
