SOLUTION: The sum of the squares of three consecutive integers is 194. What are the integers?
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Question 122716: The sum of the squares of three consecutive integers is 194. What are the integers?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X^2+(X+1)^2+(X+2)^2=194
X^2+X^2+2X+1+X^2+4X+4=194
3X^2+6X+5-194=0
3X^2+6X-189=0
(3X-21)(X+9)=0
3X-21=0
3X=21
X=21/3
X=7 ANSWER.
X+9=0
X=-9 ANSWER.
PROOF
7^2+8^2+9^2=194
49+64+81=194
194=194
-9^2-8^2-7^2=194
81+64+49=194
194=194
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