SOLUTION: The perimeter of a rectangle is 76 cm. The length of the rectangle is eight more than four times its width. What are the dimensions of the rectangle?

Question 122404: The perimeter of a rectangle is 76 cm. The length of the rectangle is eight more than four times its width. What are the dimensions of the rectangle?
Answer by algebrapro18(249) (Show Source): You can put this solution on YOUR website!
to do this problem you need to set up a system of equations and solve.

w = width
l = length

2l+2w = 76
l = 8+4w

Now we substitute l = 8+4w into 2l+2w = 76 and solve for w.

2(8+4w)+2w = 76 -->distribute
16+8w+2w = 76 --> combine like terms
10w+16=76 --> subtract 16 from both sides
10w = 60 --> divide both sides by 10
w = 6

now we substitute that value into the equation for l and solve for l.

l = 8+4w --> plug in w=6
l = 8+4(6)--> multiply 4 by 6
l = 8 + 24--> add
l = 32

so the length is 32 cm and the width is 6 cm.
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