SOLUTION: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width os the rectangle. I got 10 in. Is that right?
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Question 121770: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width os the rectangle. I got 10 in. Is that right?
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
Let Width=W and length=L
so L=8+2W and 2(L+W)=64
so 2(8+2W+W)=64 then 8+3W=32
then W=8 and L=24
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