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1) A printer uses 2989 digits to number the pages of a large volume book. Determine number of pages of book.
(2) If the book has x pages, determine number of pages.
Not sure how to solve.
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(1) First 9 pages from 1 to 9 inclusive use 9 digits.
so, 2989 - 9 = 2980 digits remain.
(2) Next 90 pages from 10 to 99 inclusive use 2 digits each, or 2*90 = 180 digits, in total.
So, 2980 - 180 = 2800 digits remain.
(3) Next 900 pages from 100 to 999 inclusive use 3 digits each, or 3*900 = 2700 digits, in total.
So, 2800 - 2700 = 100 digits remain.
(4) Starting from page 1000, each page requires four digits.
So, remaining 100 digits are used for 100/4 = 25 pages.
Thus, 9 + 90 + 900 + 25 = 1024 pages exhaust all 2989 digits, precisely.
ANSWER. The book has 1024 pages.
Solved.
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Part (1) is a normal Math problem, composed by a professional Math writer/composer.
Part (2) is absurdist composition, written by a person who does not care about what he writes.