SOLUTION: A sq. ft. of wrought iron weighs 40 lbs. Determine weight of a portion 11 in. by 9 in.
11 ( ? of 40 lbs.) = ? lbs.
9 ( ? of ? ) = ? lbs.
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99 sq. in.
Algebra.Com
Question 1210266: A sq. ft. of wrought iron weighs 40 lbs. Determine weight of a portion 11 in. by 9 in.
11 ( ? of 40 lbs.) = ? lbs.
9 ( ? of ? ) = ? lbs.
----------------------
99 sq. in. = ? lbs.
How do I determine the first two ?'s ?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39615) (Show Source): You can put this solution on YOUR website!
Your comparison is based on an area, and assumes a consistant thickness, for volume.
1 square foot is 12*12 square inches, or 144 square inches.
The weight for a 11*9 inch^2 portion is
pounds
Answer by ikleyn(52769) (Show Source): You can put this solution on YOUR website!
.
In your post, I see many question signs that have no any sense.
If you need help in solving Math problems, please post them to the forum as they are,
without your editing. Do not try to re-tell the problem in your own words,
since you can not do it adequately.
If you want to add your questions, or comments, or ideas,
place them SEPARATELY AFTER the problem's formulation.
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