SOLUTION: The final velocity v of an object in feet per second (noted aa ft/sec) after it slides down a frictionless inclined plane of height h feet is given by v = sqrt{64h + (v

SOLUTION: The final velocity v of an object in feet per second (noted aa ft/sec) after it slides down a frictionless inclined plane of height h feet is given by v = sqrt{64h + (v_0)^2},

Question 1208652: The final velocity v of an object in feet per second (noted aa ft/sec) after it slides down a frictionless inclined plane of height h feet is given by

v = sqrt{64h + (v_0)^2}, where v_0 is the initial velocity (in ft/sec) of the object.

A. Solve the given formula for h.

B. What is the final velocity v of an object that slides down a frictionless inclined plane of height 4 feet? Assume that the initial velocity is 0.
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!
a)
Since the h is hard to work with when it's inside a square root, we square both sides to get . Subtracting from both sides gives . Finally, dividing both sides by 64 gives .
b)
Going back to the original formula, we see that we have to plug in and from the problem statement. Doing so gives , so the final velocity is 16 ft/sec.
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