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Bob bought a pair of shoes. He also spent 1/4 of the remainder of his money on a pair of pants.
He had $189 left. If the cost of the pants was 3/7 the cost of the shoes, what is the price of the shoes.
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To avoid denominators, let 3x be the cost of the pair of pants.
Then the cost of the pair of shoes is 7x, according to the problem.
Let T be the total of money Bob had originally.
Then for the total we have this equation
T = 3x + 7x + 189. (1)
The remainder after buying the pair of shoes is (T-7x).
From the problem, we have this equation
= 3x. (2) (Bob spent 1/4 of the remainder of his money on a pair of pants)
Thus we have two equations, (1) and (2), for two unknowns x and T.
From equation (1),
T = 10x + 189. (3)
From equation (2),
T - 7x = 12x,
or
T = 12x + 7x = 19x. (4)
Now we substitute T = 19x from (4) into (3). We get
19x = 10x + 189,
19x - 10x = 189
9x = 189
x = 189/9 = 21.
Now we are in position to find the cost of the pair of shoes. It is 7x = 7*21 = 147 dollars. ANSWER
Solved.
Hi
Bob bought a pair of shoes. He also spent 1/4 of the remainder of his money on a pair of pants. He had $189 left. If the cost of the pants was 3/7 the cost of the shoes, what is the price of the shoes.
Let the amount he started with, and cost of shoes, be A and S, respectively
After buying the shoes, he had A - S left
Amount spent on pants:
Amount remaining after purchase of pants:
Since $189 remained after purchase of pants, we get:
------ Canceling GCF, 3, in numerators
Since cost of pants is the cost of the shoes (S), so we get:
----- Substituting 63 for
3S = 7(63) --- Cross-multiplying
Cost of shoes, or