.
Hi
At a carnival the ratio of females to males was 7 to 10 . The ratio of men to boys was 5 to 4.
The ratio of women to girls was 5 to 4. What fraction were children.
If there were 450 more men than women how many males were at the carnival.
~~~~~~~~~~~~~~~~~~~~~~~~~
The formulation of this problem is accessible to young students, who know fractions,
but are not familiar with equations. Therefore, it is natural to expect that the solution
is accessible for such students. Below I produce such a solution.
The ratio of men to boys was 5 to 4. It is the same as to say that the ratio of boys to men was 4 to 5.
The ratio of women to girls was 5 to 4. It is the same as to say that the ratio of girls to women was 4 to 5.
At this point, we see that it would be ideally, if you could count men by groups of 5,
as well as to count women by groups of 5.
The ratio of women to men was 7 to 10 (given). 7:10 is the same as 14:20, the same as 21:30,
the same as 28:40 and the same as 35:50.
As soon as you see this pair, 35 and 50, you understand that in this case you can count the men and the women by groups of 5.
So, if there are 35 men and 50 women, it implies that there are 28 boys and 40 girls.
Now the ratio under the problem question is
boys + girls 28 + 40 68
fraction of children = ---------------- = ----------- = ------.
men + women 35 + 50 85
Divide the numerator and denominator by 17 (the common factor and the greatest common divisor)
and get the answer: the fraction of children is 4:5.
Solved.
This solution does not require using any equations.
It only requires elementary skills of manipulating fractions.