SOLUTION: A drip of hot water each second wastes g gallons. Determine amount (gal.) wa sted per month. A drip is approx .33 ml. Not sure how to solve.

Question 1207548: A drip of hot water each second wastes g gallons. Determine amount (gal.) wa
sted per month.
A drip is approx .33 ml.
Not sure how to solve.
Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
use a 30 day month
0.33 ml/drip*1 drip/second*86400 sec/day*30 days/month. Note the units at the end are ml/month
=855360 ml/month.
Now we want gal/month. so the units for the next part must be gal/ml
1 liter=0.264 gallons
1 ml is 0.0002264 gallons
1=0.000264 gal/ml
therefore, multiplying that by 855360, we get 225.82 gallons. This is the answer.
for sec in a day 60se/1 min*60 min/1 hr*24 hr/1 day=86400 sec/day
Check
855360 ml=855.360 liters and that *2.2 lb/liter=1881 lb.
one gallon is about 8.3 pounds
so 1881 lb./8.3 lb./gal units will be gal.=226.72. this is consistent with the above considering I rounded the 2.2 lb/liter and the 8.3 pounds per gallon.
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
Main part begins as 0.33 mL. per second.
Question is, how many gallons per month?

Take as 1 month is 30 days just for simplicity.

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