SOLUTION: I have been trying for two hours to get this, but I can't. Can someone PLEASE help???
A car and a bike set out at noon from the same point headed in the same direction. At 1:00
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Question 120632This question is from textbook Algebra Structure and Method
: I have been trying for two hours to get this, but I can't. Can someone PLEASE help???
A car and a bike set out at noon from the same point headed in the same direction. At 1:00 P.M., the car is 60 km ahead of the bike. Find how fast each travels, given that the car travels four times as fast as the bike.
This question is from textbook Algebra Structure and Method
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A car and a bike set out at noon from the same point headed in the same direction. At 1:00 P.M., the car is 60 km ahead of the bike. Find how fast each travels, given that the car travels four times as fast as the bike.
:
Let s = speed of the bike
then
4s = speed of the car
:
The travel time for both is given as 1 hr (noon to 1PM):
:
write a distance equation Distance = time * speed
:
Car dist - bike dist = 60 km
1(4s) - 1s = 60
4s - s = 60
3s = 60
s =
s = 20 km/hr is the speed of the bike
then
4*20 = 80 km/hr is the speed of the car
:
:
Confirm solutions by finding distance traveled by each:
1*80 = 80 km
1*20 = 20 km
-------------
dif = 60 km as given
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I need to use . There is a separate equation for
bike and car
Call the distance the car travels km
Then the distance the bike travels is km
Given:
We are starting a stopwatch at noon and stopping it at 1:00 PM, so
hr
hr
substitute for in the 2nd equation
km/hr answer
km/hr answer
check
----------------------
The difference is 60 km
OK
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