SOLUTION: Hi A football team played 38 games for a total of 70 points. 3 points for a win 1 point for a draw, no points for lost games. The team won twice as many games as they drew. How ma

Question 1206158: Hi
A football team played 38 games for a total of 70 points. 3 points for a win 1 point for a draw, no points for lost games. The team won twice as many games as they drew. How many games were lost.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

An informal solution (good mental exercise!!)....

They won twice as many games as they drew.
For each "group" of two wins and one draw, they earned 2(3)+1(1) = 6+1 = 7 points.
All together, they earned 70 points; the number of those "groups" must have been 70/7 = 10.
So they must have won 10*2 = 20 games and drawn 10*1 = 10 games.
That's a total of 20+10 = 30 games in which they earned points.
Since the total number games was 38, the number of games they lost was 38-30 = 8.

ANSWER: 8

The EXACT same solution, formally....

let x = # of games they drew
then 2x = # of games they won

At 3 points for each win and 1 point for each draw (and 0 points for each loss), they earned a total of 70 points:

# of games won: 2x = 2(10) = 20
# of games drawn: x = 10
# of games in which they earned points: 20+10 = 30
# of games they lost: 38-30 = 8

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