SOLUTION: N varies jointly with the square root of p and the cube of q. If n=72 when p=3 and q=2, find n when p=-4 and q=1/2.

Question 1205427: N varies jointly with the square root of p and the cube of q. If n=72 when p=3 and q=2, find n when p=-4 and q=1/2.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
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N varies jointly with the square root of p and the cube of q.
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Answer by ikleyn(52851) (Show Source): You can put this solution on YOUR website!
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N varies jointly with the square root of p and the cube of q. If n=72 when p=3 and q=2, find n when p=-4 and q=1/2.
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When a problem of this type says that N varies jointly as the square root of "p",
it is usually assumed that p is non-negative real number - then the real value does exist.

With negative "p" (as -4 in your question), square root of negative "p" does not exist as a real number.

Therefore, your problem, as it is posed in the post, does not make sense.

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