SOLUTION: Consider the function f(x) = x-3ln(x), 1/3 <= x <= 9 The absolute maximum value is ___ at x = ___ The absolute minimum value is ___ at x = ___ I know I need to find the CP

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Question 1204527: Consider the function f(x) = x-3ln(x), 1/3 <= x <= 9
The absolute maximum value is ___ at x = ___
The absolute minimum value is ___ at x = ___
I know I need to find the CP
f'(x) = 1 - 3/x
1-3/x = 0
1 = 1/3x
x = 3
and there are the end points at 0 and 9
f(0) = 1/3 - 3ln(1/3) = 1/3 + 3ln(3)
f(3) = 3 - 3ln(3)
f(9) = 9 - 3ln(9) = 9 - 6ln(3)
However, I put these answers in and the autograder says they are incorrect and any help is appreciated :)

Answer by ikleyn(52756)   (Show Source): You can put this solution on YOUR website!
.

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