SOLUTION: When the temperature is 32° Fahrenheit, sound travels at 1087 feet per sec. The speed increases 1 foot for each degree F increase in temperature. Determine distance across a lak

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Question 1204102: When the temperature is 32° Fahrenheit, sound travels at 1087 feet per sec. The speed increases 1 foot for each degree F increase in temperature. Determine distance across a lake if it takes 1 sec. for sound to cross lake if temperature is 45° F.
32 + 13 = 45
1087 + 13 = 1100
Rate * Time = Distance
1100 * 1 = 1100 ft.

Where am I correct ?
Answer by josgarithmetic(39838) About Me  (Show Source):
You can put this solution on YOUR website!
You want speed of sound as a function of temperature. The description is giving
information for you to fit the information into a point-slope equation for a line.

If you choose temperature F and speed Y then the description directly gives
Y-1087=1%28F-32%29
or more simply Y-1087=F-32.

Maybe you can figure out the rest.
(Yes 1100 feet per second at that temperature)

Yes. You are correct.
----


(??)
This needs to make sense, without trouble. Y-1087=1%28F-32%29
This step must be clear to you , Y-1087=F-32
Y=F-32%2B1087, and you know how and why.
Y=F%2B1055-------sound speed as a function of Fahrenheit temperature

Temperature specified was 45 degrees Fahrenheit.
so speed Y must for that be
Y=45%2B1055
Y=1100-------------This is the value for speed which you will then continue to work with.