SOLUTION: Hi
If the area of a rectangle is reduced by 54cm^2 then either the length is reduced by 9cm or its width is reduced by 3cm. What is the area of the original rectangle.
Thanks
Algebra.Com
Question 1196113: Hi
If the area of a rectangle is reduced by 54cm^2 then either the length is reduced by 9cm or its width is reduced by 3cm. What is the area of the original rectangle.
Thanks
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
w, L, the original dimensions width and length
-
Area was originally
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
A formal algebraic solution as shown by the other tutor is valid; however, you learn a lot more about solving problems (and get much better brain exercise!) by solving this one using logical reasoning.
If a reduction in the length of 9cm produces a reduction in area of 54cm^2, then the width of the rectangle is 54/9 = 6cm.
If a reduction in the width of 3cm produces a reduction in area of 54cm^2, then the length of the rectangle is 54/3 = 18cm.
ANSWER: The area of the rectangle is 18*6 = 108cm^2.
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