SOLUTION: Hi The sum of Sofia and her mothers age is twice the difference between their ages. 5 years ago Sofia's mother is 4 times as old as Sofia. How old are they now. Thank you

Question 1195175: Hi
The sum of Sofia and her mothers age is twice the difference between their ages. 5 years ago Sofia's mother is 4 times as old as Sofia. How old are they now.
Thank you
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Some of the wording is unclear. Taken as "mother WAS four times as old as Sofia":
d,m;

-
d+m=2m-2d
2m-2d=d+m
m-3d=0
m=3d
-
m-5=4d-20
m=4d-15
-
3d=4d-15
0=d-15
~~0=3d-15~~
~~0=d-5~~
d=15
-
Daughter Sofia is 15, and her mother is 45.

Look for any mistakes, or possibly try the other interpretation for the description.

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Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
Hi
The sum of Sofia and her mothers age is twice the difference between their ages.
5 years ago Sofia's mother is 4 times as old as Sofia. How old are they now.
Thank you
~~~~~~~~~~~~~~~

            As , the solution and the answer from the post of @josgarithmetic
            (5 years for daughter and 15 years for her mother) are both and .

            I came to bring you a correct solution.

d,m; - d+m = 2m-2d 2m-2d = d+m m-3d = 0 m=3d - m-5=4d-20 m=4d-15 - 3d = 4d-15 0 = d-15 0 = d-15 d = 15 - Sofia is 15 years old; her mother is 45 years old. ANSWER You may check it on your own that all conditions of the problem are satisfied.

Solved.

----------------

For the safety of your brain, ignore the post by @josgarithmetic.

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