SOLUTION: A quarter is dropped from the top of the Eiffel Tower. Determine amount of time until quarter hits the ground.
Height of tower; 984 ft.
Quarter mass; 5.67 grams.
Check my
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Question 1194440: A quarter is dropped from the top of the Eiffel Tower. Determine amount of time until quarter hits the ground.
Height of tower; 984 ft.
Quarter mass; 5.67 grams.
Check my calculations, please.
S = 16t^2
984 = 16t^2
984 - 16t^2 = 16t^2 - 16t^2
-16t^2 + 984 = 0
-16t^2 + 984 - 984 = 0 - 984
-16t^2 = -984
-16t^2 / -16 = -984 / -16
t^2 = 61.5
Taking square root:
t = + 7.84, - 7.84
t = 7.84 sec.
Not sure if I used correct formula.
Found 2 solutions by math_tutor2020, Alan3354:
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
You used the correct free-fall formula
S = 16t^2
t = time elapsed
S = approximate vertical distance traveled
You also have the correct steps and correct answer.
The mass can be ignored entirely, as it plays no role in the free-fall time.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A quarter is dropped from the top of the Eiffel Tower. Determine amount of time until quarter hits the ground.
Height of tower; 984 ft.
Quarter mass; 5.67 grams.
Check my calculations, please.
S = 16t^2
984 = 16t^2
984 - 16t^2 = 16t^2 - 16t^2
-16t^2 + 984 = 0
-16t^2 + 984 - 984 = 0 - 984
-16t^2 = -984
-16t^2 / -16 = -984 / -16
t^2 = 61.5
Taking square root:
t = + 7.84, - 7.84
t = 7.84 sec.
Not sure if I used correct formula.
===========================
You added several "steps" that accomplished nothing.
984 = 16t^2
984 - 16t^2 = 16t^2 - 16t^2
-16t^2 + 984 = 0
-16t^2 + 984 - 984 = 0 - 984
-16t^2 = -984 ***** This is where you started.
===================
If air resistance is neglected, the mass is not relevant.
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