SOLUTION: When Kim Seng bought 8 identical CD he was short $28. When he bought 4 identical CD and 3 tapes he had $17 left. If each tape cost $5 how much money did he have at first. Thanks

Question 1189211: When Kim Seng bought 8 identical CD he was short $28. When he bought 4 identical CD and 3 tapes he had $17 left. If each tape cost $5 how much money did he have at first.
Thanks
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let a = amt of money he had at first
let c = cost of each CD
:
When Kim Seng bought 8 identical CD he was short $28.
a = 8c - 28
When he bought 4 identical CD and 3 tapes he had $17 left.
If each tape cost $5
a = 4c + 3(5) + 17
a = 4c + 15 + 17
a = 4c + 32
a=a, therefore, find c
8c - 28 = 4c + 32
8c - 4c = 32 + 28
4c = 60
c = 60/4
c = $15 for each CD
:
how much money did he have at first?
a = 8(15) - 28
a = 120 - 28
a = $92 amt he had at first
:
:
Check in the 2nd equation
a = 4(15) + 32
a = $92
:

Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.

Just the very first phrase " When Kim Seng bought 8 identical CD he was short $28 " makes no sense and is lame.

Indeed, having short, Kim Seng (as anyone else) would not be able to buy 8 CDs.

Watch and track your writing ( ! )

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