SOLUTION: The table below contains the birth weights in grams of 26 African American babies born at BayState Medical Center in Springfield, Massachusetts in 1986. Compute a 95% confidence in
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Question 1187604: The table below contains the birth weights in grams of 26 African American babies born at BayState Medical Center in Springfield, Massachusetts in 1986. Compute a 95% confidence interval for birth weight.
Weight
2535
2819
2942
2954
2927
2941
2956
3034
3077
3296
3365
3407
3467
3794
3835
1143
1730
1931
2101
2165
2258
2351
2403
2359
2428
2457
a)Find the point estimate for the birth weights. Round your answer to 2 decimal places.
b)Determine the value of tc.Round your answer to 5 decimal places.
c)Find the margin of error for the confidence interval. Round your answer to 1 decimal place.
d)Construct the confidence interval for birth weights. Enter your answer as an open interval of the form (a,b) and round to the nearest integer.
e)Babies weighing less than 2500 grams are considered to be of low birth weight. Can you conclude that the average birth weight is greater than 2500 grams?
Yes, the entire confidence is above 2500.
No conclusions can be drawn since the confidence interval contains
2500.
No, the entire confidence interval is below 2500.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean or point estimate is 2718.27 gm
s=639.11 gm
t(df=25, 0.975)=2.060
half-interval is t*s/sqrt(n)
=2.060*639.11/5
=263.31 gm
the interval s therefore (2455.96 gm, 2981.58 gm) or (2456, 2982) gm
No, since 2500 gm is in the CI, cannot conclude average birth rate is different from 2500 gm
Not clear why need five decimal places given the data, and I did not address that.
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